(2x+3)(x^2-4x+2)=

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Solution for (2x+3)(x^2-4x+2)= equation: 


Simplifying
(2x + 3)(x2 + -4x + 2) = 0

Reorder the terms:
(3 + 2x)(x2 + -4x + 2) = 0

Reorder the terms:
(3 + 2x)(2 + -4x + x2) = 0

Multiply (3 + 2x) * (2 + -4x + x2)
(3(2 + -4x + x2) + 2x * (2 + -4x + x2)) = 0
((2 * 3 + -4x * 3 + x2 * 3) + 2x * (2 + -4x + x2)) = 0
((6 + -12x + 3x2) + 2x * (2 + -4x + x2)) = 0
(6 + -12x + 3x2 + (2 * 2x + -4x * 2x + x2 * 2x)) = 0
(6 + -12x + 3x2 + (4x + -8x2 + 2x3)) = 0

Reorder the terms:
(6 + -12x + 4x + 3x2 + -8x2 + 2x3) = 0

Combine like terms: -12x + 4x = -8x
(6 + -8x + 3x2 + -8x2 + 2x3) = 0

Combine like terms: 3x2 + -8x2 = -5x2
(6 + -8x + -5x2 + 2x3) = 0

Solving
6 + -8x + -5x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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